0=4.9t^2+3t-2

Solution for 0=4.9t^2+3t-2 equation:

0=4.9t^2+3t-2

We move all terms to the left:

0-(4.9t^2+3t-2)=0

We add all the numbers together, and all the variables

-(4.9t^2+3t-2)=0

We get rid of parentheses

-4.9t^2-3t+2=0

a = -4.9; b = -3; c = +2;
Δ = b2-4ac
Δ = -32-4·(-4.9)·2
Δ = 48.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{48.2}}{2*-4.9}=\frac{3-\sqrt{48.2}}{-9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{48.2}}{2*-4.9}=\frac{3+\sqrt{48.2}}{-9.8}
$